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Calculation of the engine power
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Engine power
How do I calculate the required drive power for a hydraulic pump?
Which motor (kW) do I need?
Following formula is used to calculate the required drive power :
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> > > Formula (1) |
P = Engine Power [kW]
p = Pump Pressure [bar]
Q = Flow rate [l/min]
510 = 600*Efficiency 0,85
The Flow Rate of the pump can be calculated the following way:
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> > > Formel (2) |
Q = Flow rate [l/min]
Vg= geometric flow rate of the pump [cm³/U]
n = Speed of the drive motor [R/min]
To drive gear pumps with electric motors only engines with 1000, 1500 oder 3000R/min are possible. The optimal speed is 1500R/min!
It is important to note that E-motors can be overloaded by 1.4-times temporarily. Petrol or Diesel motors are not able to do this.
Example wood splitter: A small E-motor will do, because the required force is needed only temporarily, almost no force is needed during no-load and return stroke which gives the motor time to cool down.
Example:
A power unit for a wood splitter.
A pressure of 200bar and a flow rate of 20l/min are needed.
Formula (1) can calculate the required E-motor power:
P = 200bar * 20l/min / 510 = 7,84kW
In this case the nominal three-phase motor with 7,5kW and 1500R/min would be chosen.
The next step is to calculate the flow rate of the pump by changing Formula (2) to Vg:
Vg = Q * 1000 / n > > > Formula (3)
Vg = 20l/min * 1000 / 1500R/min = 13,3cm³/U
In this case a gear pump with 14cm³/U.
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